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思路：倒序单调栈。弹出所有 ≤ 当前身高的元素（这些人都能被看到），count 为弹出数量；若栈非空，还能看到栈顶（第一个更高的人），故 +1。能看到的人数 = count + (栈非空 ? 1 : 0)。
。业内人士推荐体育直播作为进阶阅读
Овечкин продлил безголевую серию в составе Вашингтона09:40
Трамп высказался о непростом решении по Ирану09:14
。业内人士推荐WPS下载最新地址作为进阶阅读
Трамп высказался о непростом решении по Ирану09:14，推荐阅读体育直播获取更多信息
Lenovo seems to be mulling the idea of putting more AI on people's desks. The other two concepts it brought to MWC are both tabletop AI companion devices.